If a force of 5 N is applied to the spring, it will be compressed by 0.5 cm.
| December 18, 2020 | education
If a force of 5 N is applied to the spring, it will be compressed by 0.5 cm. Determine the extension of the spring if a weight of 700 g is suspended from it.
F = k∆x means k = F / ∆x.
k = 5 / 0.5 = 10H / cm.
F = k∆x means ∆x = F / k. (Since the spring is the same, the stiffness is the same):
Fynp = Fт = mg = 0.7 * 9.8≈7Н
∆x = 7H / 10H / cm = 0.7cm = 0.007m
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