If a trolley weighing 350 kg moves along horizontal rails with an acceleration of 0.15 m / s² with a resistance force of 12 N, then the horizontal force under which the trolley moves is ..
According to Newton’s second law, we find what the resulting force acts on the trolley Fres = ma = 350 * 0.15 = 52.5N
Then the traction force of the trolley is Fres + Fc = 52.5 + 12 = 64.5N
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