If an elastic steel spring under the action of a force of 20n was awarded 4 cm, then its cruelty is equal to ..
| July 2, 2021 | education
Initial data: F (force acting on the elastic steel spring) = 20 N; Δx (elastic spring elongation) = 4 cm (0.04 m).
We express the stiffness of an elastic steel spring from the formula: F = -Fcont. = k * Δx, whence k = F / Δx.
Calculation: k = 20 / 0.04 = 500 N / m.
Answer: The elastic steel spring has a stiffness of 500 N / m.
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