If, during isochoric heating of a gas taken at a temperature of 27 ° C, its pressure increased from 140 kPa to 210 kPa

If, during isochoric heating of a gas taken at a temperature of 27 ° C, its pressure increased from 140 kPa to 210 kPa, then the temperature change will be

First, let’s translate T into Kelvin: 27 ° C = 300K
isochoric process – V = const, P / T = const
the pressure increased by 1.5 times, which means from the formula above, the temperature also increased by 1.5 times so that equilibrium remains
T2 = 300 * 1.5 = 450K
temperature change:
ΔТ = 450-300 = 150K