If, during the dehydrogenation of 112 liters of butane, butadiene-1,2 was obtained, then a volume

If, during the dehydrogenation of 112 liters of butane, butadiene-1,2 was obtained, then a volume of hydrogen was formed.

To solve the problem, we compose the equation:
C4H10 = 2H2 + C4H6 – dehydrogenation reaction, hydrogen was obtained;
H3C – CH2 – CH2 – CH3 = 2H2 + H2C = C = CH – CH3 (butadiene – 1.2);
Let’s make the calculations:
M (C4H10) = 58 g / mol;
Y (C4H10) = 1 * 112 / 22.4 = 5 mol;
Let’s make the proportion:
5 mol (C4H10) – X mol (H2);
-1 mol – 2 mol from here, X mol (H2) = 5 * 2/1 = 10 mol;
Let’s calculate the volume of hydrogen:
V (H2) = 10 * 22.4 = 224 HP
Answer: during the reaction, hydrogen with a volume of 224 liters was formed.