If in a circle a chord perpendicular to the diameter divides it into a segment of 25 cm and 9 cm

If in a circle a chord perpendicular to the diameter divides it into a segment of 25 cm and 9 cm, then the length of the chord is equal.

Since the diameter AB intersects the chord CD at a right angle, he divides it into two equal segments. CK = DK.

Let CK = DK = X cm.

By the property of intersecting chords, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

CK * DK = AK * BK.

X ^ 2 = 9 * 25 = 225.

X = CK = DK = 15 cm.

CD = 15 * 2 = 30 cm.

Answer: The chord length is 30 cm.



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