If the body slides without friction from a 12 m high slide onto a horizontal surface, where

If the body slides without friction from a 12 m high slide onto a horizontal surface, where the friction force acts and the coefficient of friction is 0.05, then what path will it take along the horizontal surface until it comes to a complete stop?

h = 12 m.

g = 10 m / s2.

μ = 0.05.

S -?

Let’s use the law of conservation of energy. When moving, the potential energy of the body En passes into internal energy. The friction force Ftr performs mechanical work A equal to the potential energy of the body at the beginning of the movement En: A = En.

En = m * g * h.

A = Ftr * S.

The friction force is determined by the formula: Ftr = μ * m * g.

m * g * h = μ * m * g * S.

S = m * g * h / μ * m * g = h / μ.

S = 12 m / 0.05 = 240 m.

Answer: on a horizontal surface until a complete stop, the body will travel a path S = 240 m.