If the center angle AOB of the circle centered at point O and radius r is 60 degrees

If the center angle AOB of the circle centered at point O and radius r is 60 degrees, then the chord AB is? Find the chord AB.

Let’s draw the segments OA and OB, which are the radii of the circle, OA = OB = r cm.

Then triangle AOB is isosceles, and since the central angle AOB, by condition, is equal to 60, then triangle AOB is equilateral, AB = OB = OA = r.

Answer: The length of the chord AB is equal to the radius of the circle.