If the flow rate of water in the canal per second is 0.25 m3, then with a channel width of 1.5 m and a water depth of 0.6 m, what is its flow rate.
Q = 0.25 m3 / s (cubic meter per second) – water flow rate in the canal;
a = 1.5 meters – channel width;
b = 0.6 meters – channel depth.
It is required to determine v (m / s) – the speed of water flow.
Let us find the specific sectional area of the channel:
s = a * b = 1.5 * 0.6 = 0.9 m2 (square meters).
Then, to determine the speed of the current, you must use the following formula:
Q = v * s, from here we find that:
v = Q / s = 0.25 / 0.9 = 0.28 m / s (the result has been rounded to one hundredth).
Answer: the water in the channel flows at a speed equal to 0.28 m / s.
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