If the pressure of an ideal gas has doubled, and the average kinetic energy of its molecules
| December 8, 2020 | education
If the pressure of an ideal gas has doubled, and the average kinetic energy of its molecules has decreased by 2 times, then the concentration …
Initial:
P = 2 / 3nE
n1 = 3P / 2E
After setting new conditions:
2P = 2 / 3n * E / 2
n2 = 6P / E
Now divide n1 by n2
n1 / n2 = (3P / 2E) / (6P / E) = 1/4
4n1 = n2
This means that the concentration has increased by 4 times.
Answer: concentration increased by 4 times
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