If two cyclists leave points A and B at the same time towards each other, they will meet in 18 minutes.

| January 15, 2021 | education

If two cyclists leave points A and B at the same time towards each other, they will meet in 18 minutes. The first cyclist can cover this distance in 1/2 hour. How long will the second cyclist cover this distance.

1/2 hour = 1/2 * 60 = 60/2 = 30 minutes.
Suppose the distance between point A and point B is 1.
In this case, since the first cyclist passes it in 1/2 hour, his conditional speed will be:
1/30 = 1/30 of the way per minute.
The speed of the cyclists’ convergence will be:
1/18 = 1/18 of the way per minute.
Find the speed of the second cyclist.
For this, we subtract the conditional speed of the first cyclist from the approach speed.
1/18 – 1/30 = (common denominator 90) = 5/90 – 3/90 = 2/90 = 1/45.
So he will travel this path for:
1 / 1/45 = 1 * 45/1 = 45 minutes.
Answer: 45 min.



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