# If two cyclists leave points A and B at the same time towards each other, they will meet in 18 minutes.

**If two cyclists leave points A and B at the same time towards each other, they will meet in 18 minutes. The first cyclist can cover this distance in 1/2 hour. How long will the second cyclist cover this distance.**

1/2 hour = 1/2 * 60 = 60/2 = 30 minutes.

Suppose the distance between point A and point B is 1.

In this case, since the first cyclist passes it in 1/2 hour, his conditional speed will be:

1/30 = 1/30 of the way per minute.

The speed of the cyclists’ convergence will be:

1/18 = 1/18 of the way per minute.

Find the speed of the second cyclist.

For this, we subtract the conditional speed of the first cyclist from the approach speed.

1/18 – 1/30 = (common denominator 90) = 5/90 – 3/90 = 2/90 = 1/45.

So he will travel this path for:

1 / 1/45 = 1 * 45/1 = 45 minutes.

Answer: 45 min.