In △ ABC ∠A = 62∘, ∠B = 68∘. Which side of the triangle is the smallest?

The sum of the interior angles of a triangle is 180 degrees. It follows that the angle C will be 50 °, since 180-62-68 = 50.

Angle C is the smallest of all: 62> 50 <68, therefore AB will be the smallest side, since it lies opposite the smallest angle in the triangle.



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