In 0.005 s, the magnetic flux penetrating the closed loop decreases from 9 mVb to 4 mVb

In 0.005 s, the magnetic flux penetrating the closed loop decreases from 9 mVb to 4 mVb. Determine the EMF of induction in this circuit.

Task data: Δt (duration of magnetic flux change in a closed loop) = 0.005 s; F1 (initial magnetic flux in a closed loop) = 9 mVb (9 * 10-3 Vb); F2 (final value of magnetic flux) = 4 mVb (4 * 10-3 Vb).

The EMF of induction in a given closed loop is determined by the formula: ε = | ΔФ / Δt | = | (Ф1 – Ф2) / Δt |.

Calculation: ε = (9 * 10-3 – 4 * 10-3) / 0.005 = 1 V.

Answer: In this closed loop, the EMF of induction is 1 V.