In 10 seconds, the body covered 100 meters, in the next 10 seconds, another 100 meters.

In 10 seconds, the body covered 100 meters, in the next 10 seconds, another 100 meters. Can it be argued that the body moves evenly?

Initial data: t1 (first time of body movement) = 10 s; S1 (first distance traveled) = 100 m; t2 (second movement time) = 10 s; S2 (three times the distance covered) = 100 m.

For the uniform movement of the body, the equality must be fulfilled: V = const and V1 = S1 / t1 = S2 / t2 = V2 (the body must travel equal distances in equal intervals of time).

Check: V1 = 100/10 = 10 m / s and V2 = 100/10 = 10 m / s; V1 = V2 (correct).

Answer: The body moves evenly.