In 100 grams of 30% sodium hydroxide (NaOH) solution, 22.4 liters of carbon dioxide (CO2)

In 100 grams of 30% sodium hydroxide (NaOH) solution, 22.4 liters of carbon dioxide (CO2) were dissolved. Calculate the mass of the salt formed.

Reaction of sodium hydroxide with carbon dioxide.
2NaOH + CO2 = Na2CO3 + H2O.
Determine the mass of alkali in the solution.
m (NaOH) = W (NaOH) • m (solution) / 100% = 30% • 100 g / 100% = 30 g.
Let’s find the number of moles of the starting materials.
n (NaOH) = m / Mr = 30 g / 2 * 40 g / mol = 0.375 mol.
n (CO2) = 22.4 l / 22.4 mol / l = 0.1 mol.
The calculation of the mass of sodium carbonate is carried out according to the lack.
m (Na2CO3) = n • Mr = 0.1 mol • 106 g / mol = 106 g.