In 12 hours, the mass of the radioactive isotope decreased 64 times. Find the half-life.
| July 3, 2021 | education
These tasks: t (elapsed time from the beginning of decay) = 12 hours; m / m0 (decrease in the mass of the taken radioactive isotope) = 64 r.
The half-life of the taken radioactive isotope can be expressed from the formula: m = m0 * 2 -t / T.
m / m0 = 2 -t / T.
64 = 2 -12 / T.
2 ^ 6 = 2 -12 / T.
6 = -12 / T.
T = 12/6 = 2 hours (in SI T = 7200 s).
Answer: The half-life of the taken radioactive isotope is 7200 seconds.
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