In 20 s, the lift moves a load weighing 300 kg to a height of 10 m. Determine the power of the lift.

Given: t (duration of the lift) = 20 s; m (mass of the transported cargo) = 300 kg; h (lifting height) = 10 m.
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
Decision:
We calculate the power of the used lift by the formula: N = A / t = m * g * h / t.
Calculation: N = A / t = 300 * 10 * 10/20 = 1.5 * 10 ^ 3 W (1.5 kW).
Answer: The used lift has a power of 1.5 kW.