In 20 seconds, the crane lifts a load weighing 5,000 N vertically up to a height of 10 m.

In 20 seconds, the crane lifts a load weighing 5,000 N vertically up to a height of 10 m. What mechanical power does it develop during this lifting?

Given: t (operating time of the crane used) = 20 s; h (lifting height) = 10 m; P (weight of the lifted load) = 5000 N.

The required mechanical power, which the used crane developed during the lifting of the load, is determined by the formula (the movement of the load will be considered uniform): N = F * V = P * S / t = P * h / t.

Let’s make a calculation: N = 5000 * 10/20 = 2.5 * 103 W (2.5 kW).

Answer: The crane used has a mechanical power of 2.5 kW.