In 4 seconds, the body travels 16 meters, the initial speed is 0, which way the body will cover in 4 seconds.

Task data: t4 (duration of movement) = 4 s; S4 (distance covered in 4 seconds) = 16 m; V0 (initial speed) = 0 m / s.

1) Define the constant acceleration of the body under consideration: S4 = a * t4 ^ 2/2, whence a = 2 * S4 / t4 ^ 2 = 2 * 16/4 ^ 2 = 2 m / s2.

2) Calculate the distance traveled in the fourth second: S (4) = S4 – S3 = S4 – a * t3 ^ 2/2 = 16 – 2 * 3 ^ 2/2 = 16 – 9 = 7 m.

Answer: In the fourth second of movement, the body has covered a path of 7 meters.