In 400 g of water, 50 g of lead (II) nitrate was dissolved. Determine the mass fraction of lead (II) nitrate in the solution.

The solution consists of two components: 400 grams of water and 50 grams of salt.

The mass of the solution is equal to the sum of their masses:

m solution = 400 + 50 = 450 grams.

To find the mass fraction of salt, we divide the mass of salt by the mass of the solution:

C = m salt / m solution = 50/450 = 0.1111 = 11.11%;