In 5 seconds of equally slow motion, the body travels 5m and stops. What path did the body cover in 3 seconds?

Given:

L5 = 5 m – the path covered by the body in 5 seconds.

It is required to find the path L3, which the body will pass in 3 seconds.

In 5 seconds, the body will cover the path:

S5 = V0 * 5 – a * 5 ^ 2/2.

In 4 seconds, the body will cover the path:

S4 = V0 * 4 – a * 4 ^ 2/2.

Then, in 5 seconds, the body will pass a path equal to:

L5 = S5 – S4 = 5 * V0 – 25 * a / 2 – 4 * V0 + 16 * a / 2 =

= V0 – 9 * a / 2. Since L1 = 5, and V0 = 5 * a (it is known that the body stopped after the 5th second of movement, that is, V0 – a * 5 = 0), we get:

5 * a – 4.5 * a = 5

0.5 * a = 5

a = 10 m / s ^ 2.

V0 = 50 m / s

In the third second, the body will cover the path:

L3 = S3 – S2 = 3 * V0 – 9 * a / 2 – 2 * V0 + 4 * a / 2 =

= V0 – 5 * a / 2 = 50 – 5 * 5 = 50 – 25 = 25 meters.

Answer: in the third second, the body will cover a distance of 25 meters.