In a 750 aluminum pan, 2 liters of water were heated from 20 degrees to a boil. How much heat

In a 750 aluminum pan, 2 liters of water were heated from 20 degrees to a boil. How much heat is transferred to the pot of water?

Data: m1 (weight of the pan) = 750 g = 0.75 kg; V (water volume) = 2 l = 2 * 10-3 m3; t0 (initial temp.) = 20 ºС.

Constant: tboil (boiling point of water) = 100 ºС; C1 (specific heat capacity of aluminum) = 920 J / kg * K); C2 (specific heat capacity of water) = 4200 J / (kg * K); ρ (water density) = 1000 kg / m3.

Formula: Q = Q1 (pot heating) + Q2 (water heating) = C1 * m1 * (tboil – t0) + C2 * V * ρ * (tboil – t0) = (tboil – t0) * (C1 * m1 + C2 * V * ρ).

Calculation: Q = (100 – 20) * (920 * 0.75 + 4200 * 1000 * 2 * 10-3) = 727200 J.