In a balloon with a capacity of 300m3 there is hydrogen at a temperature of 27 degrees C

In a balloon with a capacity of 300m3 there is hydrogen at a temperature of 27 degrees C and a pressure of 10 in the fifth Pa. Determine the mass of hydrogen.

Given:

V = 300 m³;

T = 27 C = 300 K;

p = 10⁵ Pa;

R = 8, 31 J / mol * K

m hydrogen =?

Solution:

Let’s use the Mendeleev-Clapeyron equation:

pV = m / M RT.

Let us express the mass m from the equation:

m = pVM / RT.

M – molar mass of hydrogen H2 is found as 2 atoms * m of one atom.

M = 2 g / mol.

Substitute the available values in the formula for mass m.

m = 10⁵ Pa * 300 m³ * 2 g / mol / 8.31 J / mol * K * 300 K = 24,067 kg ≈ 24 tons.

Answer: 24 tons.