In a brass calorimeter weighing 150 g, containing 200 g of water at 15 ° C, an iron weight of 260 g was

In a brass calorimeter weighing 150 g, containing 200 g of water at 15 ° C, an iron weight of 260 g was lowered at a temperature of 100 ° C. Determine the total constant temperature. Disregard heat loss.

To calculate the value of the total constant temperature of the calorimeter, water and weight, we use the equation: Сж * mг * (tg – t) = (Сl * mk + Sv * mw) * (t – tvk).

Data: Szh – beats. heat capacity of iron (Сж = 460 J / (kg * ºС)); mg – weight of the weight (mg = 260 g = 0.26 kg); tg – initial temperature of the weight (tg = 100 ºС); Sl – beats. heat capacity of brass (Сl = 400 J / (kg * ºС)); mk is the mass of the calorimeter (mk = 150 g = 0.15 kg); St. – beats. heat capacity of water (Sv = 4200 J / (kg * ºС)); mw is the mass of water (mw = 200 g = 0.2 kg); tvk – initial temperature of water and calorimeter (tvk = 15 ºС).

Calculation: 460 * 0.26 * (100 – t) = (400 * 0.15 + 4200 * 0.2) * (t – 15).

11960 – 119.6t = 900t – 13500.

1019.6t = 25460 and t = 25460 / 1019.6 = 24.97 ºС.

Answer: The total constant temperature of the calorimeter, water and weight is 24.97 ºС.