In a circle 240 m long, two skaters came out at the same time, the first at a speed of 11 m / s

In a circle 240 m long, two skaters came out at the same time, the first at a speed of 11 m / s, the second at a speed of 7 m / s in how many minutes will they equal?

For a skater traveling at a higher speed to catch up with a skater traveling at a slower speed, he needs to go one more lap longer than the “slow” one. At the same time, the “fast” skater will pass this circle at the speed of a relatively “slow” skater:

11 – 7 = 4 m / s.

Now let’s determine how long it takes for the “fast” skater to cover the length of one circle – we divide the length of the circle by the relative speed of the “fast” skater:

240: 4 = 60 s “fast” skater will catch up with “slow”

Answer: in 1 minute the skaters will meet.