In a circle centered at point O The diameters AD and BC are drawn, the angle OCD is 30
| September 15, 2021 | education
In a circle centered at point O The diameters AD and BC are drawn, the angle OCD is 30 ° find the value of the angle OAB.
The ВСD triangle is rectangular, since the ВDC angle is based on the ВС circle diameter, then the СD angle = 180 – 90 – 30 = 60.
Triangle ABD is rectangular since the angle ABD is based on the diameter AD. Then the angle OAB = ABD – DBC = 90 – 60 = 30.
The AOB triangle is isosceles, since OA and OB are the radii of the circle, then the angle OAB = OBA = 30.
Answer: The value of the angle OAB is 30.
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