In a circle centered O AC and BD are diameters. The center angle AOD is 142 degrees. Find the inscribed angle ACB.

Angle AOB adjacent to angle AOD.

Since the sum of adjacent angles is 180, the angle AOB = (180 – 142) = 38.

The central angle AOB rests on the arc AB as well as the inscribed angle ACB, then the angle ACB = AOB / 2 = 38/2 = 19.

Answer: The value of the inscribed angle ACB is 19.



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