In a circle centered on AC and BD diameters. The center angle of the AOD is 86 degrees. Find the inscribed angle ACB.
| February 15, 2021 | education
Angle AOD = ВOС = 86 as vertical angles. The VOС triangle is isosceles, since OB = OС = R, then the angle OСВ = OBC = (180 – 86) / 2 = 47.
The inscribed angle ACB is equal to the angle OCB of the triangle BOС. Angle ACB = 47.
Answer: Angle ACB is 47.
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