In a circle centered on the AC and BD diameters, the inscribed angle ACD = 46 Help find the angle AOD.

The COD triangle is isosceles, since OС = OD = R.

Then the angle ODC = OCD = AC = 46.

Angle COD = (180 – 46 – 46) = 88.

The angles COD and AOD are adjacent, then the angle AOD = (180 – 88) = 92.

Answer: The value of the angle AOD is 92.

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