Let’s draw a perpendicular OH, which will be the desired value.
Triangle AOB is isosceles, OA = OB = R = 1.4 m. Then the height OH is also the median and bisector of triangle AOB, and then AH = BH = AB / 2, angle AOB = AOB / 2 = 120/2 = 60 …
In a right-angled triangle AOH, the angle OAH = (180 – 90 – 60) = 30, then the leg OH = OA / 2 = 1.4 / 2 = 0.7 m.
Answer: The distance from the center of the circle to the chord is 0.7 m.
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