In a circle, the radius of which is 1.4m, determine the distance from the center to the chord that contracts the spirit of 120 degrees.

Let’s draw a perpendicular OH, which will be the desired value.

Triangle AOB is isosceles, OA = OB = R = 1.4 m. Then the height OH is also the median and bisector of triangle AOB, and then AH = BH = AB / 2, angle AOB = AOB / 2 = 120/2 = 60 …

In a right-angled triangle AOH, the angle OAH = (180 – 90 – 60) = 30, then the leg OH = OA / 2 = 1.4 / 2 = 0.7 m.

Answer: The distance from the center of the circle to the chord is 0.7 m.