In a circle with center О АС and BD-diameters. The angle АСВ is equal to 26 “Find the angle AOD.
| February 5, 2021 | education
Let’s build a chord СD. The ВСD triangle is rectangular, since the inscribed angle of the ВСD is based on the diameter of the circle. Then the angle OСD = 90 – ВСO = 90 – 26 = 64.
The inscribed angle of AСD and the central angle of AOD are based on the arc of ABP, then the angle AOD = 2 * AСD = 2 * 64 = 128.
Answer: The AOD angle is equal to 128.
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