In a circle with center O AC and BD are diameters. The center angle of the AOD is 112 degrees. Find the inscribed angle ACB.
Angle BOC = AOD = 112 as the vertical angles at the intersection of the diagonals AC and BD.
The ВOС triangle is isosceles, since OB = OС = R.
Then the angle OBC = OCВ = (180 – ВOС) / 2 = (180 – 112) / 2 = 34.
Angle ACB = OCB = 34.
Answer: The ACB angle is 340.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.