In a circle with center O AC and BD diameters. The central angle of AOD is 38. Find the inscribed angle ACB.
| April 2, 2021 | education
The inscribed angle is equal to half of the corresponding central angle.
angle ACB = ½ angle AOB.
The angles AOD and AOB are adjacent. The sum of adjacent angles is 180 degrees.
AOB + AOD = 180;
AOB = 180 – AOD;
AOB = 180 – 38 = 142.
Knowing the value of the central angle AOB, we find the degree measure of the inscribed angle ACB.
ACB = ½ * 142 = 71.
Answer. 71.
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