In a circle with center O AC and BD diameters the central angle of the AOD is 20 find the inscribed angle ACB
| May 29, 2021 | education
Angle BOC = AOD = 20 as vertical angles at the intersection of diameters AC and BD. The triangle BOS is isosceles, since OB = OС = R. Then the angle OСB = OBC = (180 – 20) / 2 = 80.
Angle ACB = OCB = 80.
Answer: The ACB angle is 80.
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