In a circle with center O, segments ac and bd are diameters. Angle aod is 148 degrees. Find angle ACB.
| March 9, 2021 | education
Let’s write down the values of all angles at the intersection of two diameters. <aod = <boc = 148 ° like vertical angles. <boa = 180 ° – <aod = 180 ° – 148 ° = 32 °.
The desired angle <bca is the inscribed angle that rests on the arc ab. which is measured by the center angle, <boa = 32 °. Then <acb = 1/2 (<boa) = 1/2 * (32 °) = 16 °.
Answer: <acb = 16 °.
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