In a circle with center O, segments AC and BD diameters. The angle is 44 degrees. Find the angle ACB.
| February 17, 2021 | education
Since AC b BD are diameters, then BO and CO are radii, then triangle BOC is isosceles. Since the angles at the base are equal in an isosceles triangle, the OCB will be:
1/2 * (180 – 44) = 136/2 = 68 degrees.
It is easy to see that the desired ACB angle is equal to the found OCB angle.
Answer: 68 degrees.
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