In a circle with center O, the diameter AC and the chord AB were drawn, the angles BAC = 40. Find the BOC angle
| October 2, 2021 | education
<B is based on the AC diameter, therefore <ABC = 90 °.
<BCO = 180 ° – (40 ° + 90 °) = 50 °.
The BOC triangle is isosceles because the OB and OS sides are equal to the radius of the circle.
The angles adjacent to the base of the BC triangle are equal:
<OBC = <OCB = 50 °.
<BOC = 180 ° – (<OBC + <OCB) = 180 – (50 ° + 50 °) = 80 °.
Answer: <BOC = 80 °.
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