In a circle with center O, the segment AB and CD, the diameters of the angle AOD is 148 °, find the angle ACB.
| July 24, 2021 | education
The AOC angle is adjacent to the AOD angle, then AOC = 180 – 148 = 32.
The AOC triangle is isosceles, then the angle OAC = OCA = (180 – 32) / 2 = 74.
The BOC angle is adjacent to the AOC angle, then the BOC angle = 180 – 32 = 148.
The ВOС triangle is isosceles, then the angle ACВ = OBC = (180 – 148) / 2 = 16.
Then the angle ACB = 74 + 16 = 90.
Answer: The ACB angle is 90.
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