In a circle with center O there are line segments AC and BD diameters. central angle AOD = 116. find the inscribed corner ACB.

The AOB angle is adjacent to the AOD angle, then the AOB angle = (180 – AOD) = (180 – 116) = 64.

The central angle AOB rests on the arc AB, then the degree measure of the arc AB = 64.

The inscribed angle ACB also rests on the arc AB, then the angle ACB = 64/2 = 32.

Answer: The inscribed angle ACB is 32.

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