In a closed vessel, mix 30 g of nitric oxide (II) and excess oxygen. Calculate the mass of the reaction product.

In this task, we will determine the mass of the resulting compound.

2NO + 2O2 = 2NO2.

Determine the molar mass of bivalent and tetravalent nitrogen oxide.

M (NO) = 14 + 16 = 30 g / mol.

M (NO2) = 14 + 16 * 2 = 46 g / mol.

Let’s make a proportion. Determine the mass of the resulting nitrogen oxide.

30 g NO – x g NO2.

2 * 30 g / mol – 2 * 46 g / mol.

Let’s define x.

X = (30 * 2 * 46) / (2 * 30) = 46 g / mol.

This means that the mass of tetravalent nitric oxide is 46 g / mol.

Answer: the mass is 46 g / mol.