In a closed vessel there is a gas under a pressure of 500 kPa. What pressure will be established in this vessel

In a closed vessel there is a gas under a pressure of 500 kPa. What pressure will be established in this vessel if, after opening the tap, 4/5 of the mass of gas escapes

To find the pressure established in the specified closed vessel, we use the equality: Pн / mн = R * T / (V * M) = Pк / mк, from where we can express: Pк = Pн * mк / mн.

Variables: Pн – initial pressure in a closed vessel (Pn = 500 kPa); mk (remaining gas mass) = 1/5 mn (initial gas mass).

Let’s make a calculation: Pk = Pn * mk / mn = 500 * 1/5 m1 / m1 = 500/5 = 100 kPa.

Answer: The pressure established in the indicated closed vessel is 100 kPa.