In a coil with an inductance of 0.4 H, an EMF of 20 V self-induction occurs.
| August 15, 2021 | education
In a coil with an inductance of 0.4 H, an EMF of 20 V self-induction occurs. Find the average rate of change of the current in the coil. Given: L = 0.4 H, E si = 20 B. Find: I / t -?
To calculate the value of the average rate of change of the current in the specified coil, we use the formula: εi = L * ΔI / Δt, whence we express: ΔI / Δt = εi / L.
Variables: εi – EMF generated in the specified coil (εi = 20 V); L – inductance (L = 0.4 H).
Calculation: ΔI / Δt = εi / L = 20 / 0.4 = 50 A / s.
Answer: The average rate of current change in the specified coil is 50 A / s.
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