In a coil with an inductance of 0.4 H, an EMF of 20 V self-induction occurs.

In a coil with an inductance of 0.4 H, an EMF of 20 V self-induction occurs. Find the average rate of change of the current in the coil.

Initial data: L (inductance of the taken coil) = 0.4 H; Εis (the value of the EMF generated in the coil) = 20 V.

The average rate of change of the current in the coil can be expressed from the formula: Εis = -L * I ‘, whence ΔI / Δt = I’ = -Εis / L.

Let’s make the calculation: I ‘= -20 / 0.4 = -50 A / s.

Answer: The rate of change of the current in the taken coil is -50 A / s.