In a coil with an inductance of 5 mH, a magnetic flux of 2 * 10 ^ -2Vb is created. What is the current in the coil?
November 19, 2020 | education
| considering this problem, we can understand that the magnetic flux is equal to the inductance multiplied by the current strength, so the current strength will be equal to 2 * 10-²Vb ÷ 5 * 10⁻³H = 4 A
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