In a coil with inductance 0.25 EMF of self-induction 10. How much will the current strength
| September 9, 2021 | education
In a coil with inductance 0.25 EMF of self-induction 10. How much will the current strength in the coil increase in 1 second?
EMF = 10 V.
L = 0.25 H.
t = 1 s.
ΔI -?
According to Faraday’s law of electromagnetic induction, the electromotive force of self-induction of the EMF in the coil is determined by the formula: EMF = L * ΔI / t, where L is the inductance of the coil, ΔI is the change in the current in the coil, t is the time of the change in the current in the coil.
The formula for determining the change in the current strength in the coil ΔI will have the form: ΔI = EMF * t / L.
ΔI = 10 V * 1 s / 0.25 H = 40 A.
Answer: the current in the coil has increased by ΔI = 40 A.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
