In a conductor with a resistance of 2 Ohm connected to an element with an EMF of 1.1 V, the current strength is 0.5 A

In a conductor with a resistance of 2 Ohm connected to an element with an EMF of 1.1 V, the current strength is 0.5 A, what is the current when the element is short-circuited?

1) We find out the internal resistance of the taken element: ε = I * (R + r), whence we express: r = ε / I – R, where ε is the EMF of the taken element (ε = 1.1 V); I is the current in the formed circuit (I = 0.5 A); R – resistance (external) of the conductor (R = 2 Ohm).

Calculation: r = ε / I – R = 1.1 / 0.5 – 2 = 2.2 – 2 = 0.2 Ohm.

2) Let’s calculate the required current in case of short circuit of the taken element (R → 0): Isc = ε / r.

Calculation: Isc = ε / r = 1.1 / 0.2 = 5.5 A.

Answer: With a short circuit of the taken element, the current will be 5.5 A.