In a conductor with a resistance of 2 Ohm connected to an element with an EMF of 1.1 V
| May 14, 2021 | education
In a conductor with a resistance of 2 Ohm connected to an element with an EMF of 1.1 V, the current strength is 0.5 A. Determine the internal resistance of the source.
R = 2 ohms.
I = 0.5 A.
EMF = 1.1 V.
r -?
According to Ohm’s law for a closed loop, the current in the circuit I is directly proportional to the electromotive force of the current source EMF and is inversely proportional to the sum of the external resistance R and internal resistance r: I = EMF / (R + r).
R + r = EMF / I.
The internal resistance of the current source r will be determined by the formula: r = EMF / I – R.
r = 1.1 V / 0.5 A – 2 ohms = 0.2 ohms.
Answer: the current source has an internal resistance r = 0.2 Ohm.
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