In a copper conductor, the cross-sectional area of which is 0.17mm * 2, the current strength is 0.15A.

In a copper conductor, the cross-sectional area of which is 0.17mm * 2, the current strength is 0.15A. Determine the current density in this conductor.

S = 0.17 mm ^ 2 = 17 * 10 ^ -7 m ^ 2.
I = 0.15 A.
J -?
The current density J in a uniform cylindrical conductor is determined by the formula: J = I / S.
Where I is the current in the copper conductor, S is the cross-sectional area of the copper conductor.
J = 0.15 A / 17 * 10 ^ -7 m ^ 2 = 0.0088 * 10 ^ 7 A / m ^ 2 = 88000 A / m ^ 2.
Answer: the current density in a copper conductor is J = 88000 A / m ^ 2.