In a cylinder with a volume of 50 liters at a temperature of 170 degrees Celsius there is carbon dioxide 5 mega pascal find the mass gas
V = 50 l = 0.05 m3.
t = 170 ° C.
P = 5 MPa = 5 * 10 ^ 6 Pa.
M (CO2) = 0.044 kg / mol.
R = 8.31 m2 * kg / s2 * K * mol.
Carbon dioxide has the molecular formula CO2, so its molar mass is M (CO2) = 0.044 kg / mol.
We express the gas mass from the Mendeleev-Cliperon law: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is molar mass of gas.
m = P * V * M / R * T.
T = 273 + t.
T = 273 + 170 ° C = 443 ° K.
m = 5 * 10 ^ 6 Pa * 0.05 m3 * 0.044 kg / mol / 8.31 m2 * kg / s2 * K * mol * 443 ° K = 3 kg.
Answer: the cylinder contains m = 3 kg of carbon dioxide.
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