In a diode, an electron approaches the anode at a speed of 8 Mm / s. Find the anode voltage.

To find the value of the anode voltage, we will use the equality: me * V ^ 2/2 = Ekmax = qe * U, whence we express: U = me * V ^ 2 / 2qe.
Constants and variables: me – electron mass (me = 9.11 * 10 ^ -31 kg); V is the speed of approach of the electron to the anode (V = 8 Mm / s = 8 * 10 ^ 6 m / s); qе is the electron charge (qе = -1.6 * 10 ^ -19 C).
Calculation: U = me * V ^ 2 / 2qe = 9.11 * 10 ^ -31 * (8 * 10 ^ 6) ^ 2 / (2 * (1.6 * 10 ^ -19)) = 182.2 V …
Answer: The anode voltage is 182.2 V.